A 25 kg uniform solid sphere with a 20 cm radius is suspended by a vertical wire such that the point of suspension is vertically above the center of the sphere. A torque of 0.10 N-m is required to rotate the sphere through an angle of 1.0 rad and then maintain the orientation. If the sphere is then released, its time period of the oscillation will be:
A
π second
B
π second
C
2 π second
D
4 π second
Text Solution
Verified by ExpertsThe correct answer is:
D
I = 
mR 2 = 
× 25 × (0.2) 2 = 
τ = Cθ
c = 
= 
= 0.1
T = 2 π 
= 
= 2 π × 2 = 4 π secs
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